PythonSqlite3以字典形式返回查询结果方法介绍

cursor = conn.cursor(pymysql.cursors.DictCursor)

但官方文档里已经有预留了相应的实现方案。

def dict_factory(cursor, row): 
 d = {} 
 for idx, col in enumerate(cursor.description): 
 d[col[0]] = row[idx] 
 return d

使用这个函数代替conn.raw_factory属性即可。

def dict_factory(cursor, row): 
 d = {} 
 for idx, col in enumerate(cursor.description): 
 d[col[0]] = row[idx] 
 return d con = sqlite3.connect(":memory:") #打开在内存里的数据库
con.row_factory = dict_factory
cur = con.cursor()
cur.execute("select 1 as a")
print cur.fetchone()["a"]